Example 1: Graph a line in standard form using its intercepts
Graph the line 2x - 3y = 6 in the xy-plane, and state its slope.
- 2x - 3y = 6
Show solution
- Find the x-intercept by setting y = 0: 2x - 3(0) = 6, so 2x = 6 and x = 3. The point (3, 0) is on the line.
Setting y to zero erases the whole y term, which is why intercepts are the fastest points to find in this form.
- Find the y-intercept by setting x = 0: 2(0) - 3y = 6, so -3y = 6 and y = -2. The point (0, -2) is on the line.
Dividing 6 by -3 gives -2, not 2. Keep the sign of the coefficient.
- Plot (3, 0) and (0, -2) and draw the straight line through them, extending it in both directions.
Two points determine a line, so the graph is now fixed.
- Compute the slope from the two intercepts: m = (0 - (-2)) / (3 - 0) = 2 / 3.
Subtract the y-values in the same order you subtract the x-values.
- Confirm by solving for y: -3y = -2x + 6, so y = (2/3)x - 2, which shows the same slope 2/3 and the same intercept -2.
Dividing every term by -3 flips both signs; forgetting the constant is the usual slip.
- Check a third point: x = 6 gives y = (2/3)(6) - 2 = 4 - 2 = 2, and 2(6) - 3(2) = 12 - 6 = 6, so (6, 2) satisfies the original equation.
Answer: The line passes through (3, 0) and (0, -2), its slope is 2/3, and its slope-intercept form is y = (2/3)x - 2.