Example 1: Two conditional probabilities from one table
In a group of 120 students, 60 studied with a group and 60 studied alone. Of those who studied with a group, 42 passed; of those who studied alone, 28 passed. Find the probability that a student passed, given that the student studied with a group. Then find the probability that a student studied with a group, given that the student passed.
| Study method | Passed | Did not pass | Total |
|---|---|---|---|
| Studied with a group | 42 | 18 | 60 |
| Studied alone | 28 | 32 | 60 |
| Total | 70 | 50 | 120 |
Show solution
- Read the first condition: given that the student studied with a group. That restricts you to the group-study row, whose total is 60.
The condition fixes the denominator before you look at anything else. Underline it.
- Count the numerator inside that row: 42 of the group-study students passed.
- Form the fraction: 42/60 = 7/10 = 0.7.
Both 42 and 60 are divisible by 6, which gives 7/10.
- Read the second condition: given that the student passed. That restricts you to the passed column, whose total is 42 + 28 = 70.
The condition has flipped from a row to a column, so the denominator changes even though the question sounds almost identical.
- Count the numerator inside that column: 42 of the students who passed had studied with a group.
- Form the fraction: 42/70 = 3/5 = 0.6.
The numerator was 42 both times. Only the denominator changed, and that is where the whole question lives.
Answer: The probability of passing given group study is 42/60 = 0.7, and the probability of group study given passing is 42/70 = 0.6.