Math
geometryeasy~20 min

The Pythagorean Theorem

You will be able to identify the hypotenuse of any right triangle no matter how it is drawn, find a missing hypotenuse or leg with a² + b² = c², recognize the Pythagorean triples that let you skip the arithmetic, simplify a radical answer, use the distance formula as the theorem on a coordinate plane, and spot the right triangle hidden inside a rectangle, ladder, or coordinate problem.

Introduction

The Pythagorean theorem is the single most-used geometry fact on both the SAT and the ACT. It says that in any right triangle the two shorter sides, the legs, and the longest side, the hypotenuse, are locked together by one equation: a² + b² = c². Give a test writer any two of the three sides and the third is determined, which is exactly why so many questions hand you two lengths and ask for a third.

What makes the theorem worth a full lesson is not the formula, which you already know, but where it hides. The SAT rarely says the words right triangle. Instead it asks for the diagonal of a rectangle, the distance between two points on a coordinate plane, how far up a wall a ladder reaches, or the length of a chord in a circle, and expects you to see the right triangle inside. The ACT does the same and adds the reverse question: here are three side lengths, is the triangle right?

The two skills that separate a fast, correct answer from a slow, wrong one are naming the hypotenuse correctly before you write anything, and recognizing the handful of whole-number triples that show up again and again. This lesson builds both, then walks through the places the tests bury the triangle.

Game plan

How to attack these questions on test day.
  1. 1

    Find the right angle first, then name c

    Before you write a single square, put your finger on the right angle. The side across from it is the hypotenuse, and it is the only side that can be c. It is also always the longest side, so if you are handed three numbers the largest one is c whether or not the figure is drawn with c on the slant. A triangle drawn with its hypotenuse flat along the bottom is a favorite trap, because your eye wants to call the slanted side the hypotenuse.

  2. 2

    Scan for a triple before you square anything

    Memorize 3-4-5, 5-12-13, 8-15-17, and 7-24-25, and remember that every multiple of a triple is also a triple. When two sides of a right triangle are 6 and 8, you should see 3-4-5 doubled and write 10 without computing 36 + 64. When the hypotenuse is 26 and a leg is 10, that is 5-12-13 doubled, so the other leg is 24. The tests use these triples constantly precisely because they keep the answer choices whole numbers.

  3. 3

    Know when the answer stays a radical, and how to write it

    If the sum or difference of squares is not a perfect square, the answer is a radical, and multiple-choice answers will show it simplified. Pull out the largest perfect-square factor: √52 = √(4 times 13) = 2 √13. Do not convert to a decimal unless the choices are decimals. On a digital SAT student-produced response question the answer box cannot hold a square root symbol, so there you enter the decimal, such as 7.211, rounded or truncated to fit.

  4. 4

    Draw the hidden right triangle

    When a problem mentions a diagonal, a distance between two points, a ladder, a ramp, the height of a kite, or a radius meeting a tangent line, sketch the right triangle before doing any algebra. A rectangle's diagonal splits it into two right triangles whose legs are the length and width. Two points on a coordinate plane are joined by a hypotenuse whose legs are the horizontal and vertical changes. Once the triangle is on paper the question is a routine two-sides-given problem.

  5. 5

    Sanity check with two inequalities

    The hypotenuse must be longer than either leg and shorter than the two legs added together. If you find a leg that is bigger than the hypotenuse, you added when you should have subtracted. If you find a hypotenuse of 14 from legs of 6 and 8, you added the legs instead of their squares. These two checks take three seconds and catch most of the errors students actually make on this topic.

Theory

A right triangle is a triangle with one 90-degree angle. The two sides that meet at that right angle are the legs, usually written a and b, and the side opposite the right angle is the hypotenuse, written c. The hypotenuse is always the longest side, because the largest angle in any triangle sits across from the longest side and 90 degrees is the largest angle a right triangle can have. The Pythagorean theorem states that a² + b² = c²: the squares of the two legs add up to the square of the hypotenuse. The equation holds for every right triangle and for no other triangle, which is why identifying the right angle is step one of every problem.

The theorem is a statement about areas. If you build a square on each side of a right triangle, the square on the hypotenuse has exactly the same area as the two squares on the legs put together. For a 3-4-5 triangle the squares have areas 9, 16, and 25, and 9 + 16 = 25. This is also why the equation squares the sides rather than adding them directly: the lengths themselves do not add up, since 3 + 4 is not 5, but the areas of the squares do.

To find a missing hypotenuse, square both legs, add, and take the square root: c=a2+b2c = \sqrt{a^2 + b^2}. To find a missing leg, square the hypotenuse, subtract the square of the known leg, and take the square root: a=c2b2a = \sqrt{c^2 - b^2}. The difference between the two is the sign in the middle, and getting it wrong is the most common error on this topic. You add when the unknown is the hypotenuse and subtract when the unknown is a leg, because the hypotenuse squared is the biggest of the three squares and the other two must be taken away from it. A side length is always positive, so you keep only the positive square root.

A Pythagorean triple is a set of three whole numbers that satisfies the equation, and the tests lean on a small family of them: 3-4-5, 5-12-13, 8-15-17, and 7-24-25. Multiplying every side of a triple by the same number gives another triple, since scaling all three sides by k scales all three squares by k² and the equation still balances. So 6-8-10, 9-12-15, and 12-16-20 are all the 3-4-5 triangle in disguise, and 10-24-26 is 5-12-13 doubled. Recognizing a triple turns a squaring-and-rooting problem into a glance.

The distance formula is the Pythagorean theorem wearing coordinates. For two points (x₁, y₁) and (x₂, y₂), the horizontal change x₂ - x₁ and the vertical change y₂ - y₁ are the two legs of a right triangle, and the distance between the points is the hypotenuse: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}. Because each change is squared, it does not matter which point you call the first one or whether a change comes out negative. What does matter is subtracting correctly when a coordinate is negative, since 2 - (-4) is 6, not -2.

The theorem also runs in reverse. If the three sides of a triangle satisfy a² + b² = c² with c the longest side, the triangle must be a right triangle; if a² + b² is larger than c² the triangle is acute, and if it is smaller the triangle is obtuse. The ACT likes to ask which set of side lengths could form a right triangle, and the test is always the same: square the two smaller numbers, add, and compare with the square of the largest.

One piece of test logistics is worth knowing. The digital SAT gives you a reference sheet on every math question that lists a² + b² = c² along with the special right triangles, so you never have to trust memory for the formula itself. The ACT provides no formula sheet at all, so there the formula, the common triples, and the add-versus-subtract rule all have to come from you.

Worked figures

The parts of a right triangle

The right angle is at C, marked with the small square. The legs a and b meet at C, and the hypotenuse c runs across from the right angle between A and B. The theorem a² + b² = c² relates the three sides; here the legs are 8 and 6, so c² = 64 + 36 = 100 and c = 10.

Figure 1
abc (hypotenuse)ABCa² + b² = c²

The 3-4-5 triangle

The most common right triangle on either test. Its legs are 3 and 4 and its hypotenuse is 5, and the squares check: 9 + 16 = 25. Any triangle with sides in the ratio 3 to 4 to 5, such as 6-8-10 or 9-12-15, is this triangle scaled up.

Figure 2
4359 + 16 = 25

The 5-12-13 triangle

The second triple to memorize. The legs are 5 and 12, the hypotenuse is 13, and 25 + 144 = 169. Notice how much longer and flatter it is than the 3-4-5: the shape of a triple is fixed, so when a problem gives a hypotenuse of 13 and a leg of 5, the other leg must be 12.

Figure 3
1251325 + 144 = 169

Pythagorean triples and the multiples the tests use

Every row is a right triangle with whole-number sides, and every multiple of a row is another one. When two sides of a right triangle match a row, or a multiple of a row, write the third side down without squaring anything.

Table 1
Triple (a, b, c)Check: a² + b² = c²Multiples you will see
3, 4, 59 + 16 = 256-8-10, 9-12-15, 12-16-20, 15-20-25
5, 12, 1325 + 144 = 16910-24-26, 15-36-39
8, 15, 1764 + 225 = 28916-30-34
7, 24, 2549 + 576 = 62514-48-50

The distance formula is the theorem on a coordinate plane

To find the distance between (1, 2) and (7, 10), draw the horizontal and vertical legs. The horizontal leg is the change in x, 7 - 1 = 6, and the vertical leg is the change in y, 10 - 2 = 8. The distance d is the hypotenuse: d² = 36 + 64 = 100, so d = 10.

Figure 4
24682468106 = 7 - 18 = 10 - 2d(1, 2)(7, 10)

The hypotenuse is not always the slanted side

This is a 6-8-10 right triangle drawn with its hypotenuse flat along the bottom. The right angle is at the top, so the side across from it, the bottom side, is the hypotenuse. A student who calls the slanted 8 the hypotenuse and writes 6² + 10² = c² gets √136, which is wrong. Always locate the right angle, then read across from it.

Figure 5
10 (hypotenuse)6836 + 64 = 100, so c = 10

Worked examples

Try each one before opening the solution.

Example 1: Find the hypotenuse

A right triangle has legs of length 9 and 12. What is the length of the hypotenuse?

Show solution
  1. Locate the right angle: the sides 9 and 12 meet at it, so they are the legs and the unknown side across from it is the hypotenuse c.

    The unknown is c, so you will add the squares. Decide add or subtract before touching the numbers.

  2. Write the theorem with the known sides in place: 9² + 12² = c².
  3. Square each leg: 81 + 144 = c².
  4. Add: c² = 225.
  5. Take the positive square root: c = √225 = 15.

    A length is never negative, so the negative root is discarded without comment.

  6. Check against a triple: 9-12-15 is 3-4-5 multiplied by 3, so 15 is right. Also 15 is bigger than 12 and smaller than 9 + 12 = 21, as a hypotenuse must be.

    Spotting the triple at the start would have skipped every step in between.

Answer: The hypotenuse is 15.

Example 2: Find a leg

A right triangle has a hypotenuse of length 25 and one leg of length 7. What is the length of the other leg?

Show solution
  1. Identify the sides: 25 is the largest number and is opposite the right angle, so c = 25. The known leg is 7 and the unknown leg is a.

    The unknown is a leg, so you will subtract from the hypotenuse squared.

  2. Write the theorem: a² + 7² = 25².
  3. Square the known sides: a² + 49 = 625.
  4. Subtract 49 from both sides: a² = 625 - 49 = 576.

    Adding here, 625 + 49 = 674, would produce a leg of about 26, longer than the hypotenuse, which is impossible.

  5. Take the positive square root: a = √576 = 24.
  6. Check: 7-24-25 is one of the standard triples, and 24 is shorter than 25.

Answer: The other leg is 24.

Example 3: Distance between two points on a coordinate plane

What is the distance between the points (-4, 3) and (2, -5) in the xy-plane?

The right triangle between (-4, 3) and (2, -5)
-5-4-3-2-11234-6-5-4-3-2-1123468d(-4, 3)(2, -5)
Show solution
  1. Draw the right triangle: the horizontal leg runs from (-4, 3) to (2, 3), and the vertical leg runs from (2, 3) down to (2, -5). The distance is the hypotenuse.

    The right angle is at (2, 3), the point that shares its x-coordinate with one point and its y-coordinate with the other.

  2. Find the horizontal leg from the change in x: 2 - (-4) = 2 + 4 = 6.

    Subtracting a negative adds. Writing 2 - 4 = -2 here is the single most common error on distance questions.

  3. Find the vertical leg from the change in y: -5 - 3 = -8, so the leg is 8 units long.

    The sign disappears when you square, so only the size of the change matters.

  4. Apply the theorem: d² = 6² + 8² = 36 + 64.
  5. Add: d² = 100.
  6. Take the square root: d = 10.

    Legs of 6 and 8 are 3-4-5 doubled, so the hypotenuse had to be 10.

Answer: The distance is 10.

Example 4: A ladder against a wall

A 20-foot ladder leans against a vertical wall with its base 12 feet from the wall on level ground. How high up the wall does the ladder reach? If the base is then pulled out to 16 feet from the wall, how far does the top of the ladder slide down?

Show solution
  1. Sketch the right triangle: the wall is a vertical leg, the ground is a horizontal leg of 12, and the ladder is the hypotenuse of 20, since the wall and the ground meet at a right angle.

    The ladder is the longest of the three, and it is across from the right angle, so it is c. Do not use 20 as a leg.

  2. Write the theorem with the height h unknown: h² + 12² = 20².
  3. Square: h² + 144 = 400.
  4. Subtract 144 from both sides: h² = 256.
  5. Take the positive square root: h = 16 feet.

    12-16-20 is 3-4-5 multiplied by 4, which confirms the arithmetic.

  6. Repeat for the new position with the base 16 feet out: h² + 16² = 20², so h² = 400 - 256 = 144 and h = 12 feet.

    The ladder does not change length, so 20 is still the hypotenuse in the second triangle.

  7. Subtract the two heights to get the drop: 16 - 12 = 4 feet.

    The question asks how far the top slides, not the new height. Reread the last line before you answer.

Answer: The ladder reaches 16 feet up the wall. When the base is pulled out to 16 feet, the top drops to 12 feet, a slide of 4 feet.

Practice

Check your understanding 1

A right triangle has legs of length 6 and 8. What is the length of the hypotenuse?

Check your understanding 2

The hypotenuse of a right triangle is 17 and one of its legs is 8. What is the length of the other leg?

Check your understanding 3

A rectangle has a length of 15 inches and a width of 8 inches. What is the length of a diagonal of the rectangle, in inches?

Check your understanding 4

In the xy-plane, what is the distance between the points (-1, 4) and (3, -2)?

Check your understanding 5

Which of the following sets of side lengths could be the three sides of a right triangle?

Common mistakes

Using the wrong side as the hypotenuse. The hypotenuse is the side across from the right angle and it is always the largest number, no matter how the triangle is rotated on the page. When a triangle is drawn with its longest side flat along the bottom, students routinely call the slanted side c and get a radical instead of a whole number. Find the right angle first and read across from it.

Adding when you should subtract. When the hypotenuse is given and a leg is missing, the leg squared is c² minus the other leg squared. Adding produces a leg longer than the hypotenuse, which cannot happen. If your leg comes out bigger than c, you added.

Forgetting the square root, or forgetting to square. Legs of 6 and 8 give c² = 100, and the hypotenuse is 10, not 100. Going the other way, 6 + 8 = 14 is not the hypotenuse either, because the theorem adds the squares of the legs, not the legs. Answer choices on both tests routinely include the sum of the legs and the unrooted c² as distractors.

Splitting the radical. √(a² + b²) is not a + b, and √(16 + 36) is not 4 + 6. The square root of a sum cannot be taken term by term. Add first, then take the root of the total, and simplify by pulling out perfect-square factors: √52 = 2 √13.

Mishandling negative coordinates in the distance formula. The change in x between (-4, 3) and (2, -5) is 2 - (-4) = 6, not 2 - 4 = -2. Write the subtraction out with the parentheses in place. The sign of a change never matters because it gets squared, but the size of the change does, and a dropped negative changes the size.

Applying the theorem to a triangle that is not right. The equation a² + b² = c² holds only when there is a 90-degree angle, and the tests will happily show you a triangle with a 60-degree angle and two sides and wait for you to reach for the theorem anyway. If no right angle is given or provable, the theorem does not apply, and the question is usually about special right triangles, trigonometry, or the reverse test for whether a triangle is right at all.