A right triangle is a triangle with one 90-degree angle. The two sides that meet at that right angle are the legs, usually written a and b, and the side opposite the right angle is the hypotenuse, written c. The hypotenuse is always the longest side, because the largest angle in any triangle sits across from the longest side and 90 degrees is the largest angle a right triangle can have. The Pythagorean theorem states that a² + b² = c²: the squares of the two legs add up to the square of the hypotenuse. The equation holds for every right triangle and for no other triangle, which is why identifying the right angle is step one of every problem.
The theorem is a statement about areas. If you build a square on each side of a right triangle, the square on the hypotenuse has exactly the same area as the two squares on the legs put together. For a 3-4-5 triangle the squares have areas 9, 16, and 25, and 9 + 16 = 25. This is also why the equation squares the sides rather than adding them directly: the lengths themselves do not add up, since 3 + 4 is not 5, but the areas of the squares do.
To find a missing hypotenuse, square both legs, add, and take the square root: c = a 2 + b 2 c = \sqrt{a^2 + b^2} c = a 2 + b 2 . To find a missing leg, square the hypotenuse, subtract the square of the known leg, and take the square root: a = c 2 − b 2 a = \sqrt{c^2 - b^2} a = c 2 − b 2 . The difference between the two is the sign in the middle, and getting it wrong is the most common error on this topic. You add when the unknown is the hypotenuse and subtract when the unknown is a leg, because the hypotenuse squared is the biggest of the three squares and the other two must be taken away from it. A side length is always positive, so you keep only the positive square root.
A Pythagorean triple is a set of three whole numbers that satisfies the equation, and the tests lean on a small family of them: 3-4-5, 5-12-13, 8-15-17, and 7-24-25. Multiplying every side of a triple by the same number gives another triple, since scaling all three sides by k scales all three squares by k² and the equation still balances. So 6-8-10, 9-12-15, and 12-16-20 are all the 3-4-5 triangle in disguise, and 10-24-26 is 5-12-13 doubled. Recognizing a triple turns a squaring-and-rooting problem into a glance.
The distance formula is the Pythagorean theorem wearing coordinates. For two points (x₁, y₁) and (x₂, y₂), the horizontal change x₂ - x₁ and the vertical change y₂ - y₁ are the two legs of a right triangle, and the distance between the points is the hypotenuse: d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 . Because each change is squared, it does not matter which point you call the first one or whether a change comes out negative. What does matter is subtracting correctly when a coordinate is negative, since 2 - (-4) is 6, not -2.
The theorem also runs in reverse. If the three sides of a triangle satisfy a² + b² = c² with c the longest side, the triangle must be a right triangle; if a² + b² is larger than c² the triangle is acute, and if it is smaller the triangle is obtuse. The ACT likes to ask which set of side lengths could form a right triangle, and the test is always the same: square the two smaller numbers, add, and compare with the square of the largest.
One piece of test logistics is worth knowing. The digital SAT gives you a reference sheet on every math question that lists a² + b² = c² along with the special right triangles, so you never have to trust memory for the formula itself. The ACT provides no formula sheet at all, so there the formula, the common triples, and the add-versus-subtract rule all have to come from you.